x^2+10=5x-7

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Solution for x^2+10=5x-7 equation: 



x^2+10=5x-7

We move all terms to the left:

x^2+10-(5x-7)=0

We get rid of parentheses

x^2-5x+7+10=0

We add all the numbers together, and all the variables

x^2-5x+17=0

a = 1; b = -5; c = +17;
Δ = b2-4ac
Δ = -52-4·1·17
Δ = -43
Delta is less than zero, so there is no solution for the equation

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